Many consumers have to renovate their new homes after they purchase them. In addition to the primary concern of the renovation, home wiring is also the homeowner's most concerned. Home wiring is a big problem, it is not big, because such projects are too small for network companies, and generally do not want to pick up such projects, except for the overall wiring of the project with a large amount of engineering; Small, because it is a very professional and complicated project for the wiring of wires in general home decoration projects.
In order to give a little reference to the home decoration wiring, the author here gives you some guidance, I hope to lift the maximum doubt for you.
First, the calculation of excipients
1. The number of statistical information points, including each room and computer room, is filled in the point distribution table;
2. Determine if it is too long? If it is too long, where should I set up the sub-wiring room, a few? If there is a sub-wiring room, the number of switches will also change accordingly.
3. Determine the direction of the reason;
4. Determine the model and length of the bridges. Calculation method: (length × width) × 0.4 / 28, the result is the number of information points, commonly used standard bridge: 300 × 100, 200 × 100, 100 × 100, 100 × 50, 50 × 50, other bridges need to be customized .
Note: If the branch reason has the same bridge model, calculate its length separately, and finally calculate the total length of the bridge model.
5, ? 25 and ? 20 tube calculation (usually 25 can be laid 6 lines, ? 20 can be 4 lines). When calculating, based on ?20, the average length of a certain information point from the bridge to the terminal needs to be 20, and if it is A, then the length of all information points needs to be calculated, that is, B=A×(total Points / 4), and actually in the project, ? 20 = 2 / 3 × B, ? 25 = 1/3 × B.
6. Calculation of angle steel (30×30). The length of the angle steel = 30cm × (the total length of the bridge m / 1.5m), that is, the average length of each angle steel is 30cm, an angle steel is required every 1.5m distance.
7. Calculation of keel (75×45). The length of the keel = 70 cm × (total points / 2), that is, each keel has a length of 70 cm and is usually arranged as a double-port panel.
8, the calculation of keel clips, pipe joints, box joints, rivets, steel saw blades and other accessories. = total auxiliary material price × 10%
9, the calculation of the bottom box (86 × 86). Number of bottom boxes = total points / 2
Second, the calculation of materials
1. Calculation of cable:
(farthest + most recent) / 2 × points × 1.1 / 305
Description:
The farthest point is from the machine room to the information point;
Recently, the information point in the computer room is generally 20 meters;
The number of points is the information point covered from the beginning of the equipment room. If there is a sub-wiring room, the number of points is the number of information points covered by the reason for starting from the sub-wiring room. 0.1 in 1.1 is the margin, that is, 10 %. 305 is 305 meters in length per box.
If there are sub-wiring rooms, they should be calculated separately and the formula is consistent. That is: the number of cables required to cover the information points in the central equipment room + the number of cables required to cover the information points in the sub-wiring area + the number of cables required to connect the sub-wiring rooms to the central equipment room.
2. Calculation of the module. The number of information points;
3, the number of dual port panels: total points / 2;
4. Calculation of 48-port patch panels. Total number of points / 48, if there are sub-wiring rooms should be calculated separately, that is, the number of information points covered by each / 48, and then added, 4U;
5. Calculation of the line manager. The 48-port patch panel does not require a line manager (included), mainly for the switch. If there is a sub-wiring room, it should be calculated separately. 1U;
6. Cabinet jumper (2m). Jump from the patch panel to the jumper of the switch + the cascade between the switches.
7, the jumper of the workstation. The total number of points;
8, RJ45 head. (Cabinet jumper + workstation jumper) × 2 × 1.1;
9, RJ45 head sheath. The number of heads for RJ45;
10. The number of three major logarithms. The distance from the weak well through the bridge to the machine room + rich (larger, because the large logarithm can not be connected);
11, 110DW2-100FT patch panel (2U). One is 100 pairs;
12, 110 through the line slot. Consistent with the number of 110 patch panels;
13, 110 back plate (4U). For: 110DW2-100FT distribution frame number / 2;
14, 110C4 connection block (10 per package).
The 110DW2-100FT distribution frame is 100 pairs, that is, 100 telephones. It consists of four parts, each part is 25 pairs, which consists of 5 C4 connection blocks and 1 C5 connection block (5×4+1×5=25). That is, 100 pairs of large logarithms require 20 C4 connection blocks and 4 C5 connection blocks.
15, 110C5 connection block (10 per package). Cit;
16, telephone jumper (disc / 100 meters). Each phone jumper takes 1.5 meters.
17, RJ11 head. The number of telephones is determined. For example, 200 telephones (200 pairs of large logarithms) require 200 RJ11 heads (the other end is directly on the RJ11 patch panel);
18, telephone cabinet (200 times). Based on the number of telephone calls;
19. Cabinet (42U, 24U). Calculate the height (U) of the 48-port patch panel, line manager, RJ11 patch panel, switch, server, etc.
Third, the configuration of the fiber
Description: There is a central computer room on the second floor, and there is a sub-wiring room. There are also one sub-wiring room for each of the 4th and 7th floors, and 6-core indoor multimode fiber is placed in each of the three sub-wiring rooms.
Mold connection: fiber consumables and ST multimode fiber optic connectors are required;
Fusion mode: Single-chip multimode ST pigtails are required, no fiber consumables and ST multimode fiber connectors are required.
The above are some calculation methods and techniques for home wiring installation, I hope to help everyone!
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